by Ben6993 » Tue Sep 15, 2015 7:52 am
A pair of entangled particles share a pair of opposite spin states. Under a hidden variable model, the particles are not entangled but each have opposite hidden spin states. If measured in the same direction they will have opposite spins measured and Alice and Bob will feel equal thermodynamic heat. If they are not measured in the same direction then they may not necessarily have opposite spin states when measured. Anyway, Alice and Bob gain heat from measurement independently of each other.
Under QM, the system does not know the states of Alice and Bob's particles, only knowing that the states are opposite. Assuming first that the two measurements are made in the same orientation, if Alice and Bob measure at exactly the same time then they share the measurement heat equally. If Alice measures before Bob, does Alice feel all the measurement heat and Bob gets none, because as soon as Alice makes a measurement, the state of Bob's particle is known before Bob makes the measurement?
Under QM, if the measurements are made in different orientations and Alice measures before Bob, knowing the outcome of Alice does not predict the outcome for Bob as they could be -- or ++ and not necessarily -+ or +-. So is the thermodynamic heat shared equally between Alice and Bob because the measured outcomes are not the simple opposite entangled states shared under QM. Or does Alice get all the heat again because the entanglement information is resolved on Alice's measurement. But is the entanglement spin states of |+ , -> ever resolved if the actual measurements of Alice and Bob were say ++.