FrediFizzx wrote:Ok, you all. Thread has gone off topic. Let's get back to the main topic of this thread or I will lock it.
Joy Christian wrote:Now I find this observation very interesting, but so far it has not attracted much interest.
gill1109 wrote:...the really interesting things in the real world experiments like Aspect's, Weihs', and so on, is that we never appear to violate the Tsirelson bound 2 sqrt 2.
Joy Christian wrote:Let me also stress once again that my model has nothing whatsoever to do with detection loophole, or any other loophole for that matter.
gill1109 wrote:Joy Christian wrote:Let me also stress once again that my model has nothing whatsoever to do with detection loophole, or any other loophole for that matter.
Amusing that your computer simulation of your model is "lifted" straight from publications about the detection loophole.
Joy Christian wrote:Amusing that at other junctures you have stressed quite stressfully that one and the same mathematical structure can describe many different physical phenomena.
gill1109 wrote:PS Florin Moldoveanu wrote me the following (note: I disagree with his correction of equation 22)I double checked Pearl's computations, and I found many problems. All checks out until formula 16 (including 16 and including appendix A and B) Then it goes downhill. (17) has a typo, the correct formula is:
mu(x) = - 1/(1-x^2)^{1/2} d/dx [(1-x^2)^{1/2} / 4x d/dx g(x) x^2]
Equation (19) is messed up big time, 1/2 g(x) is the sum of the 2 integrals over [(1-x^2)^{1/2} + x] and not the first integral over (1-x^2) + the second integral over x^2. As a consequence Eq. 23 is wrong as well, but 23 does follow from the incorrect 19. Section V of the paper is based on (23) and is invalid.
I could not obtain Eq. 20 (I got a similar slightly more complex one-I am still working on it and maybe it will simplify to 20)
Eq. 21 has a typo and should read:
h(x) = 1/4 C pi 1/(1+x)^3
Eq. 22 has a typo and should read:
rho(r) r^2 = 1/3 sin (1/2 pi r) / (1+cos(1/2 pi r))^3
It was a major pain to straighten out the math on page 1421 because it is a sloppy paper and there are many false trails one need to explore to understand the intention. On Eq. 20 I got a very similar expression but I am lacking the overall 1/1-x^2 factor outside the square brackets, and in the second integral I have an additional term of (1-z^2)^{1/2}. The first integral in the square bracket is equal with g(0)/2.
Heinera wrote:gill1109 wrote:PS Florin Moldoveanu wrote me the following (note: I disagree with his correction of equation 22)I double checked Pearl's computations, and I found many problems. All checks out until formula 16 (including 16 and including appendix A and B) Then it goes downhill. (17) has a typo, the correct formula is:
mu(x) = - 1/(1-x^2)^{1/2} d/dx [(1-x^2)^{1/2} / 4x d/dx g(x) x^2]
Equation (19) is messed up big time, 1/2 g(x) is the sum of the 2 integrals over [(1-x^2)^{1/2} + x] and not the first integral over (1-x^2) + the second integral over x^2. As a consequence Eq. 23 is wrong as well, but 23 does follow from the incorrect 19. Section V of the paper is based on (23) and is invalid.
I could not obtain Eq. 20 (I got a similar slightly more complex one-I am still working on it and maybe it will simplify to 20)
Eq. 21 has a typo and should read:
h(x) = 1/4 C pi 1/(1+x)^3
Eq. 22 has a typo and should read:
rho(r) r^2 = 1/3 sin (1/2 pi r) / (1+cos(1/2 pi r))^3
It was a major pain to straighten out the math on page 1421 because it is a sloppy paper and there are many false trails one need to explore to understand the intention. On Eq. 20 I got a very similar expression but I am lacking the overall 1/1-x^2 factor outside the square brackets, and in the second integral I have an additional term of (1-z^2)^{1/2}. The first integral in the square bracket is equal with g(0)/2.
I think Florin is actually right about Eq. 22 here. If we take Richard's cdf integral
4/3 . ( -1 / 4 + 1 / (1 + cos pi r / 2) ^2 )
and check by differentiating it back to get the distribution, we get Florin's Eq. multiplied by 4 pi.
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