Xray wrote:Thanks Gill; I'll pass your challenge on to the author. I suspect he will want know how you, in charge of the source, will code the entangled particle pairs. In other words: What inputs do you want his theory to handle? I presume his outputs will be ±1.
So please give me the link to the precise specification of the source's outputs in the challenge? Via PM please.
Because -- just in case your challenge is judged to be unrealistic -- we should limit this thread to specific criticisms of the given essay.
Thus: Can you help me, please? Can you point me to any errors in the essay?
PS: I do believe that it's only undergrad maths that's employed.
FrediFizzx wrote:In the paper that this thread is about (stay on topic, Richard), I don't understand eq. 19 to 22. Maybe you can explain more about them?
Xray wrote:4. Richard, in that you've gotten to (19)-(22): that presumably means that you've seen Bell's first fundamental error explicitly identified and corrected. You've seen the nonsense in CHSH explicitly identified and corrected. So we need to be serious in defining issues that we want clarified -- because this looks like serious business to me.
Xray wrote:Richard, I have replied to your comment at viewtopic.php?f=6&t=50
I suggest your unfocussed content should continue there.
To be fair to all, and as I understand the reasonable protocol here: this Topic requires specific and focussed content that stays on topic.
gill1109 wrote:<AB> does not stand for the average of A times B over n runs
<AC> does not stand for the average of A times C over a different n runs.
<AB> stands for what the average of A times B would be, if infinitely often a lambda was drawn at random according to the probability distribution just mentioned, and A and B were both measured and A times B was averaged.
Larsson & Gill wrote:http://arxiv.org/pdf/quant-ph/0312035v2.pdf
The problem here is that the ensemble on which the correlations are evaluated changes with the settings, while the original Bell inequality requires that they stay the same. In effect, the Bell inequality only holds on the common part of the four different ensembles ΛAC′ , ΛAD′ ,ΛBC′ , and ΛBD′
minkwe wrote:By simply adding time as a component, there is no common part of the four ensembles, a null set, and Bell inequality collapses. This is exactly the point being made by Watson. You do not deny that fact, you admit as much in your own paper. Talk of population mean and sample averages is just a diversionary tactic IMHO.
gill1109 wrote:This is not the point made by Watson. You are completely off topic.
Watson confuses sample and population, a quite different issue.
If you want to discuss Hess and Phillip contra Gill and Larsson start a new topic.
minkwe wrote:Bell's derivation does not follow unless the probability distribution of lambda is the same for all ensembles. This is Watson's point too. You will have to find something else in the paper to criticize because the above isn't a valid critique.
gill1109 wrote:Xray wrote:Richard, I have replied to your comment at viewtopic.php?f=6&t=50
I suggest your unfocussed content should continue there.
To be fair to all, and as I understand the reasonable protocol here: this Topic requires specific and focussed content that stays on topic.
Thanks Xray, you are right. I read your other post before this one, and already gave a focussed answer there. http://www.sciphysicsforums.com/spfbb1/viewtopic.php?f=6&t=50. I'll not repeat it here.
Here are some different focussed comments.
Section 4 of Watson's viXra paper entitled "Bell’s 1964 analysis refuted" shows that Watson does not understand the notion of an ensemble or population, does not understand the difference between an experimental average and a population mean value.
Watson has made the probability distribution of lambda discrete and uniform, and converted the integrals into sums. Fine. So in the population of hidden variables, there are exactly n different value of lambda, all equally likely.
In the part of Bell's paper we are talking about:
<AB> does not stand for the average of A times B over n runs
<AC> does not stand for the average of A times C over a different n runs.
<AB> stands for what the average of A times B would be, if infinitely often a lambda was drawn at random according to the probability distribution just mentioned, and A and B were both measured and A times B was averaged.
<AC> stands for what the average of A times C would be, if infinitely often a lambda was drawn at random and A and C were both measured and A times C was averaged.
Those two thought experiments are different experiments. Different sets of infinitely many runs. But the same values of lambda will turn up in both series, and they'll both turn up equally often.
gill1109 wrote:That is not Watson's point. Watson, like you, does not distinguish between a population and a sample.
BTW, a bit off topic, but did you do my silly R computer experiment yet? And have you read chapters 13 and 16 of "Speakable and unspeakable in quantum mechanics"?
Gordon Watson wrote:We are discussing Watson (2014, v.3). So, with that understanding, could you (gill1109) couch you criticism in more precise terms, please? For example, since every one of my equations is numbered, why not be specific and say things like this: In eqn. (99) Watson calculates the sample mean and wrongly equates it to Bell 1964:(101) ... because Bell is explicit in .... Or Watson's analysis of CHSH at eqn. (97) assumes ... contrary to their assumption ... .
FrediFizzx wrote:In the paper that this thread is about (stay on topic, Richard), I don't understand eq. 19 to 22. Maybe you can explain more about them?
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